[OS X TeX] box in forms

Alain Schremmer Schremmer.Alain at verizon.net
Fri Jan 14 12:01:16 EST 2005


After playing with the suggestions from Hochhaus,  Hegewald and 
Gerhardt, whom I all thank, I am using Hochhaus' because it does exactly 
what I needed: it works in text as well as in math and lets one specify 
the height, necessary with an empty box:

The President of the United States in 
\framebox[10mm]{\parbox[l][3mm][t]{7mm}{}}
The President of the United States in 
\framebox[10mm]{\parbox[l][3mm][t]{7.5mm}{1998}}
$\frac{\framebox[4mm]{\parbox[l][2mm][c]{1.5mm}{}}^{2}-13}{\framebox[4mm]{\parbox[l][2mm][c]{1.5mm}{}}-2}$
$\frac{\framebox[4mm]{\parbox[l][2mm][c]{1.5mm}{5}}^{2}-13}{\framebox[4mm]{\parbox[l][2mm][c]{1.5mm}{5}}-2}$

There is one thing, though. The last argument before the entry in the 
box, 7mm/7.5mm/1.5mm,  moves the entry inside the box and is easily 
adjustable by trial and errror but I didn't understand "the rule". In 
Companion 2ed, page 863, parbox doesn't even have that argument!!!

Grateful regards to all.
--schremmer



Stephan Hochhaus wrote:

>
> Am 12.01.2005 um 06:42 schrieb Alain Schremmer:
>
>>    \framebox[\height + 10mm]{}
>>
>> after the example on page 861 of Companion 2ed but I could not figure 
>> how to increase the height of the box. It seems \height refers to the 
>> height of the text and \height + 10mm is then the width of the box.
>
> A horizontal box is always as high as the line it is used in. You 
> could nest some boxes like that:
>
> \framebox[5cm]{\parbox[l][2ex][t]{0mm}{}} %2ex controls the height of 
> the box
>
> Good luck :-)
>
> Stephan
>
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