[OS X TeX] Re: Beamer bug?

[Christopher Menzel]

On Oct 8, 2008, at 2:27 PM, Lantz Susan wrote:
> Chris,
>
> I have run into this same problem, with tables---and also with  
> gather*-ed and align*-ed equations---

Hi Susan, this is definitely the same bug; it seems to affect all  
tabular-style environments.

> but I was *not* using \beamertemplatetransparentcovereddynamic.

But you were using

\setbeamercovered{transparent},

which I'm pretty sure calls the same basic function.

I can offer you a workaround that I've been using via a description  
environment.  Try replacing this piece of code in your presentation:

\begin{align*}
Q_x &= Q_d - Q_b\\
\pause
Q_d &= 0.5\pi^2 D^2Nd_c\sin A\cos A\\
\pause
Q_b &= \frac{p\pi Dd_c^3\sin^2 A}{12\eta L}\\
\pause
A &= \tan\left(\frac{p}{\pi D}\right)^{-1}
\end{align*}

with this:

\begin{description}
\setlength{\itemindent}{.5in}
\setlength{\itemsep}{.125in}
\item[{\color{black}{$\mathit{Q_x}$}}] $= Q_d - Q_b$
\pause
\item[{\color{black}{$\mathit{Q_d}$}}] $= 0.5\pi^2 D^2Nd_c\sin A\cos A$
\pause
\item[{\color{black}{$\mathit{Q_b}$}}] $= \frac{\displaystyle p\pi
     Dd_c^3\sin^2 A}{\displaystyle 12\eta L}$
\pause
\item[{\color{black}{$\mathit{A}$}}] $= \tan\left(\frac{p}{\pi D} 
\right)^{-1}$
\end{description}

It's a bit of a hack, but it seems to get you more or less the effect  
you are looking for.

Cheers!

-chris