[OS X TeX] Tried comment environment in Memoir

[Alain Schremmer]

On Apr 6, 2009, at 2:43 PM, David Arnold wrote:
> \documentclass{memoir}
> \usepackage{amsmath}
> \usepackage{comment}
> \chapterstyle{bianchi}
>
> \newoutputstream{backansout}
> \newoutputstream{solutionsout}
>
> \newenvironment{Exercises}
> {\openoutputfile{\jobname.backans}{backansout}
> \openoutputfile{\jobname.solns}{solutionsout}}
> {\closeoutputstream{backansout}
> \closeoutputstream{solutionsout}}
>
> \newcounter{exercise}[section]
> \renewcommand{\theexercise}{\arabic{exercise}}
>
> \newenvironment{exercise}%
> {\refstepcounter{exercise}
> \par\noindent\textbf{\theexercise}.}
> {\par}
>
> \makeatletter
>
> \newenvironment{genericout}[1]{%
>   \@bsphack
>   \ifodd\theexercise
>     \addtostream{#1}{\protect\begin{oddexercise}{\theexercise}}%
>   \else
>     \addtostream{#1}{\protect\begin{evenexercise}{\theexercise}}%
>   \fi
>   \def\genericoutfile{#1}%
>   \writeverbatim{#1}%
>
> }{%
>
>   \endwriteverbatim
>   \ifodd\theexercise
>     \addtostream{\genericoutfile}{\protect\end{oddexercise}}%
>   \else
>     \addtostream{\genericoutfile}{\protect\end{evenexercise}}%
>   \fi
>   \@esphack
>
>
> }
>
> \newenvironment{backanswer}{%
>   \genericout{backansout}%
>
>
> }{%
>   \endgenericout
> }%
>
> \newenvironment{solution}{%
>   \genericout{solutionsout}%
>
>
> }{%
>   \endgenericout
> }%
>
> \newenvironment{oddexercise}[1]{\par\noindent\textbf{#1.}}{}
> \newenvironment{evenexercise}[1]{\par\noindent\textbf{#1.}}{}
> %\includecomment{oddexercise}
> \excludecomment{evenexercise}
>
> \begin{document}
>
> \chapter{The Whole Numbers}
>
> \section{Introduction to the Whole Numbers}
>
> Now is the time for all good men to come to the aid of their country.
> Now is the time for all good men to come to the aid of their country.
> Now is the time for all good men to come to the aid of their country.
> Now is the time for all good men to come to the aid of their country.
> Now is the time for all good men to come to the aid of their country.
> Now is the time for all good men to come to the aid of their country.
>
> \subsection{Exercises}
>
> \begin{Exercises}
>
> \begin{exercise}
> Solve for $x$:\quad $2x+3=5-2x$.
>
> \begin{backanswer}
> $1/2$
> \end{backanswer}
>
> \begin{solution}
> Isolate terms with $x$ on the left, simplify, then divide by the
> coefficient of $x$.
> \begin{align*}
> 2x+3&=5-2x\\
> 2x+2x&=5-3\\
> 4x&=2\\
> \frac{4x}{4}&=\frac{2}{4}\\
> x&=\frac{1}{2}
> \end{align*}
>
> Next, raise each side to the second power.
> \begin{align*}
> x&=\frac{1}{2}\\
> x^2&\left(\frac12\right)^2\\
> x^2&=\frac14
> \end{align*}
>
> This is the square of the solution.
> \end{solution}
>
> \end{exercise}
>
> \begin{exercise}
> Solve for $x$:\quad $2x+3=5-2x$.
>
> \begin{backanswer}
> $1/2$
> \end{backanswer}
>
> \begin{solution}
> Isolate terms with $x$ on the left, simplify, then divide by the
> coefficient of $x$.
> \begin{align*}
> 2x+3&=5-2x\\
> 2x+2x&=5-3\\
> 4x&=2\\
> \frac{4x}{4}&=\frac{2}{4}\\
> x&=\frac{1}{2}
> \end{align*}
> \end{solution}
>
> \end{exercise}
>
> \begin{exercise}
> Solve for $x$:\quad $2x+3=5-2x$.
>
> \begin{backanswer}
> $1/2$
> \end{backanswer}
>
> \begin{solution}
> Isolate terms with $x$ on the left, simplify, then divide by the
> coefficient of $x$.
> \begin{align*}
> 2x+3&=5-2x\\
> 2x+2x&=5-3\\
> 4x&=2\\
> \frac{4x}{4}&=\frac{2}{4}\\
> x&=\frac{1}{2}
> \end{align*}
> \end{solution}
>
> \end{exercise}
>
> \begin{exercise}
> Solve for $x$:\quad $2x+3=5-2x$.
>
> \begin{backanswer}
> $1/2$
> \end{backanswer}
>
> \begin{solution}
> Isolate terms with $x$ on the left, simplify, then divide by the
> coefficient of $x$.
> \begin{align*}
> 2x+3&=5-2x\\
> 2x+2x&=5-3\\
> 4x&=2\\
> \frac{4x}{4}&=\frac{2}{4}\\
> x&=\frac{1}{2}
> \end{align*}
> \end{solution}
>
> \end{exercise}
>
> \begin{exercise}
> Solve for $x$:\quad $2x+3=5-2x$.
>
> \begin{backanswer}
> $1/2$
> \end{backanswer}
>
> \begin{solution}
> Isolate terms with $x$ on the left, simplify, then divide by the
> coefficient of $x$.
> \begin{align*}
> 2x+3&=5-2x\\
> 2x+2x&=5-3\\
> 4x&=2\\
> \frac{4x}{4}&=\frac{2}{4}\\
> x&=\frac{1}{2}
> \end{align*}
> \end{solution}
>
> \end{exercise}
>
> \begin{exercise}
> Solve for $x$:\quad $2x+3=5-2x$.
>
> \begin{backanswer}
> $1/2$
> \end{backanswer}
>
> \begin{solution}
> Isolate terms with $x$ on the left, simplify, then divide by the
> coefficient of $x$.
> \begin{align*}
> 2x+3&=5-2x\\
> 2x+2x&=5-3\\
> 4x&=2\\
> \frac{4x}{4}&=\frac{2}{4}\\
> x&=\frac{1}{2}
> \end{align*}
> \end{solution}
>
> \end{exercise}
>
> \end{Exercises}
>
> \subsection{Answers}
>
> \input{\jobname.backans}
>
> \subsection{Solutions}
>
> \input{\jobname.solns}
>
> \end{document}
>

Out of sheer curiosity, I tried the above but  got the error

LaTeX Font Warning: Font shape `OT1/cmss/m/it' in size <12> not  
available
(Font)              Font shape `OT1/cmss/m/sl' tried instead on input  
line 72.

	Runaway argument?
	! Paragraph ended before \verbatim at start was complete.
	<to be read again>
	                   \par
	l.90 \begin{backanswer}

Of course, I don't even know if memoir is anywhere in Mac's guts so I  
tried book instead and got the error

	Excluding comment 'comment')
	! Undefined control sequence.
	<recently read> \chapterstyle

	l.5 \chapterstyle
	                 {bianchi}
	?

That looked plausible so I commented out
	\chapterstyle{bianchi}

which gave me this time

	Excluding comment 'comment')
	! Undefined control sequence.
	l.7 \newoutputstream
                     {backansout}
	?

But now I have no idea even what to try.

Merely curious regards
--schremmer