[OS X TeX] corrupt pdf fille

Mon Mar 17 17:34:01 EDT 2008

On Mar 17, 2008, at 4:49 PM, Javier Elizondo wrote:

> Hello everyone,
>
> I have edited a latex file with Emacs and texshop and after a while  
> of being working on it, I got a corrupted pdf file, most of the math  
> content appears not readable. And the fonts (usualy roman) are also  
> changed.
>
> Everything gets again fine if I restart the computer, and again,  
> after a while when I keep working on the file and running it a few  
> times the problem comes back. It is an easy file, and I have run the  
> file in a linux computer and everything is fine. However, it seems  
> that if I look at the file using adobe acrobat reader everything  
> seems fine.
>

Well, one likely culprit is the font cache. This is corroborated by  
the file's being "fixed" after restart and working on linux. I don't  
know if acrobat uses the same files as preview and TS.

There are some free programs that clear out caches, such as Onyx and  
fontnuke.

But maybe someone sees a problem with the code below---although it's  
not clear why it would create a good pdf on one run then not on the  
next, if the code is the same each time.

> The latex file is the following
>
> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
>
> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
> %              THIS FILE IS IN       LaTeX 2e
> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
> \documentclass[12pt,spanish, english]{article}
> \usepackage[latin1]{inputenc}
> \usepackage[spanish]{babel}
> %\usepackage{pdfsync}
> %%%%%%%%%%%%%%%%%%%%    Packages     %%%%%%%%%%%%%%%%%%%%%
> \usepackage{amscd}
> \usepackage{amsmath}
> \usepackage{amsthm}
> \usepackage{amsfonts}
> \usepackage{eucal}
> \usepackage{amsgen}
> \usepackage{amstext}
> \usepackage{amsbsy}
> \usepackage{amsopn}
> \usepackage{amssymb}
> \usepackage[all]{xy}
>
> \AtBeginDocument{\decimalpoint}
>
> \pagestyle{empty}
> %%%%%%%%%%%%%%%%%%%%      Macros      %%%%%%%%%%%%%%%%%%%%
>
>       %%%%%%%% Environments %%%%%%%%%%%
>
> \newtheorem{theorem}{Theorem}[section]
> \newtheorem{thm}[theorem]{Theorem}
> \newtheorem{lemma}[theorem]{Lemma}
> \newtheorem{proposition}[theorem]{Proposition}
> \newtheorem{corollary}[theorem]{Corollary}
>
> \theoremstyle{definition}
>
> \newtheorem{definition}[theorem]{Definition}
> \newtheorem{example}[theorem]{Example}
> \newtheorem{subexamples}[theorem]{Subexamples}
> \newtheorem{conjecture}[theorem]{Conjecture}
> \newtheorem{properties}[theorem]{Properties}
> \newtheorem{facts}[theorem]{Facts}
> \newtheorem{problem}{Problem}
> \theoremstyle{remark}
>
> \newtheorem{remark}[theorem]{Remark}
> \newtheorem{rmk}[theorem]{Remark}
> \newtheorem{notation}[theorem]{Notation}
>
>
> \newtheorem*{ack}{\bf Acknowledgement}
>
>
>        %%%%%%%%%%% Fonts %%%%%%%%%%%%
>
> %%%%%%% BlackBoardBold %%%%%%%%%%%%%%%
>
> \newcommand{\field}[1]{\ensuremath{\mathbb{#1}}}
> \newcommand{\A}{\field{A}}
> \newcommand{\C}{\field{C}}
> \newcommand{\F}{\field{F}}
> \newcommand{\N}{\field{N}}
> \newcommand{\Pp}{\field{P}}
> \newcommand{\Q}{\field{Q}}
> \newcommand{\R}{\field{R}}
> \newcommand{\T}{\field{T}}
> \newcommand{\Z}{\field{Z}}
> \newcommand{\G}{\field{G}}
> \renewcommand{\P}{\field{P}}
>
> %%%%%%% Calligraphic %%%%%%%%%%%%%%%
>
> \newcommand{\cala}{\mathcal{A}}
> \newcommand{\calb}{\mathcal{B}}
> \newcommand{\calc}{\mathcal{C}}
> \newcommand{\cald}{\mathcal{D}}
> \newcommand{\cale}{\mathcal{E}}
> \newcommand{\calf}{\mathcal{F}}
> \newcommand{\call}{\mathcal{L}}
> \newcommand{\calm}{\mathcal{M}}
> \newcommand{\caln}{\mathcal{N}}
> \newcommand{\calo}{\mathcal{O}}
> \newcommand{\calp}{\mathcal{P}}
> \newcommand{\sO}{\calo}
> \newcommand{\sS}{\mathcal{S}}
> \newcommand{\sQ}{\mathcal{Q}}
> \newcommand{\sL}{\call}
> \newcommand{\sE}{\cale}
> %%%%%%% MathBold   (lower case)  %%%%%%%%%%%%%%%
>
> \newcommand{\bone}{\mathbf{1}}
>
> \newcommand{\mba}{\mathbf{a}}
> \newcommand{\mbb}{\mathbf{b}}
> \newcommand{\mbc}{\mathbf{c}}
> \newcommand{\mbd}{\mathbf{d}}
> \newcommand{\mbe}{\mathbf{e}}
> \newcommand{\mbf}{\mathbf{f}}
> \newcommand{\mbg}{\mathbf{g}}
> \newcommand{\mbh}{\mathbf{h}}
> \newcommand{\mbi}{\mathbf{i}}
> \newcommand{\mbm}{\mathbf{m}}
> \newcommand{\mbn}{\mathbf{n}}
>
>        %%%%%%%%%%%%%%%%%% Mathfrak %%%%%%%%%%%%%%%%%%%%%%%
>
> \newcommand{\mfm}{\ensuremath{\mathfrak{m}}}
>
>
>
>        %%%%%%%%%%%% Delimiters %%%%%%%%%%%%
>
> \newcommand{\lp}{\left( }
> \newcommand{\rp}{\right) }
>
>        %%%%%%%%%%%% Spaces %%%%%%%%%%%%
>
> \newcommand{\ps}[1]{\ensuremath{\Pp^{#1}}}
> \newcommand{\spr}[2]{\ensuremath{SP^{#1}\lp{#2}\rp}}
> \newcommand{\gr}[2]{\ensuremath{G\lp{#1},{#2}\rp}}
> \newcommand{\grp}[2]{G_{#1}(\Pp^{#2})}
> \newcommand{\fl}[2]{F(#1;\Pp^{#2})}
> \newcommand{\py}{p_\infty}
> \newcommand{\cq}{/\!\!/ }
> \newcommand{\scho}[2]{\omega^{#2}_{#1}}
> \newcommand{\sch}[2]{\Omega^{#2}_{#1}}
> \newcommand{\cvp}[2]{\ensuremath{{\mathcal C}_{#1}\bigl(#2\bigr)}}
> \newcommand{\cvpd}[3]{\ensuremath{{\mathcal  
> C}_{#1,#2}\left( #3\right)}}
>        %%%%%%%%%%%% Monoids, Groups and (Co)-Homology %%%%%%%%%%%%
> \newcommand{\GL}{{\rm GL}\,}
> \newcommand{\atm}{\mbox{${\mathfrak{Atm}}$}}
> \newcommand{\atmp}{\mbox{${\mathfrak{Atm}_p}$}}
> \newcommand{\gar}[1]{\ensuremath{{\mathfrak{A}}_R\hspace{-.04cm} 
> \langle #1 \rangle }}
> %
> \newcommand{\garf}[1]{\ensuremath{{\mathfrak{A}}_{R}^{fin}\hspace{-. 
> 06cm}\langle #1 \rangle }}
> %
>
>
> \newcommand{\apx}[1]{\ensuremath{{\Pi}_{p}(#1)}}
> \newcommand{\ap}{\ensuremath{{\Pi}_{p}}}
> \newcommand{\ax}[2]{\ensuremath{\Pi_{#1}\bigl(#2\bigr)}}
> \newcommand{\alg}[2]{\ensuremath{\mathcal{A}_{#1}\bigl(#2\bigr)}}
> \newcommand{\algp}[2] 
> {\ensuremath{\mathcal{A}^{\geq}_{#1}\bigl(#2\bigr)}}
> \newcommand{\mmp}[2]{\ensuremath{M_{#1}\bigl(#2\bigr)}}
> \newcommand{\hg}[3]{\ensuremath{H_{#1}(#2,#3)}}
> \newcommand{\cg}[3]{\ensuremath{H^{#1}\lp #2,#3\rp}}
> \newcommand{\ns}[1]{\ensuremath{\mbox{NS}(#1)}}
> \newcommand{\nss}[2]{\ensuremath{{NS\bigl(#1\bigr)}{\oplus}{NS 
> \bigl(#2\bigr)}}}
> \newcommand{\pic}[3]{\ensuremath{{Pic}^{#1}_{#2}\bigl(#3 \bigr)}}
> \newcommand{\Zp}{\ensuremath{{\field{Z}}_{p}}}
> \newcommand{\Zplus}{\ensuremath{{\field{Z}}_{+}}}
>
>        %%%%%%%%%%%% SERIES AND PROJECTIVIZATIONS %%%%%%%%%%%%
>
> \newcommand{\ahcs}[2]{\ensuremath{P_{#1}^{#2}(t)}}
> \newcommand{\hcs}[2]{\ensuremath{P_{#1}^{#2}(t)}}
> \newcommand{\aecs}[2]{\ensuremath{E_{#1}\bigl(#2\bigr)}}
> \newcommand{\ecs}[2]{\ensuremath{E_{#1}\bigl(#2\bigr)}}
> \newcommand{\pb}[1]{\ensuremath{{\Pp}\bigl(#1\bigr)}}
> \newcommand{\vb}[2]{\ensuremath{{\mathcal O}_{#1}\bigl(#2\bigr)}}
> \newcommand{\eone}{\ensuremath{E\oplus{\bone}}}
> \newcommand{\eot}{\ensuremath{E_1\oplus E_2}}
> \newcommand{\efib}{\ensuremath{{\pb{E_1}\!\!\times_{W}\!\pb{E_2}}}}
> \newcommand{\us}[1]{\ensuremath{\underline{#1}}}
> %%%%%%%%%%%%%%%ARROWS%%%%%%%%%%%%%%%%%%%%
> \newcommand{\by}[1]{\stackrel{#1}{\longrightarrow}}
> \newcommand{\onto}{\twoheadrightarrow}
> \newcommand{\into}{\hookrighthttp://www.cnn.com/arrow}
> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
>      %%%%%%%%%%%%  MISCELLANEOUS  %%%%%%%%%%%%
> \newcommand{\tensor}{\otimes}
> \newcommand{\ie}{{\it i.e.\/},\/}
> \newcommand{\coker}{{\rm coker}\,}
> \newcommand{\codim}{{\rm codim}\,}
>
> \newcommand{\co}[2]{\ensuremath{\mathcal{O}_{#1}\bigl(#2\bigr)}}
> \newcommand{\eaeq}{\sim_{\text{alg}^+}}
> \newcommand{\aeq}{\sim_{\text{alg}}}
> \newcommand{\equdef}{:=}
> \DeclareMathOperator{\supp}{supp}
> %\DeclareMathOperator{\im}{im}
> %\DeclareMathOperator{\Jac}{Jac}
> \DeclareMathOperator{\Pic}{Pic}
> %\DeclareMathOperator{\Div}{Div_{T}}
> %\DeclareMathOperator{\Hom}{Hom}
> %\DeclareMathOperator{\Spec}{Spec}
> \DeclareMathOperator{\rank}{rk}
> \DeclareMathOperator{\effd}{Div_+}
>
> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% ENUMERATE %%%%%%%%%%%%%%%%%%%%%%%%
>
> \renewcommand{\theenumi}{\Roman{enumi}}
> \renewcommand{\labelenumi}{\theenumi.}
> \renewcommand{\theenumii}{\arabic{enumii}}
> \renewcommand{\labelenumii}{\theenumii.}
> \renewcommand{\theenumiii}{\arabic{enumiii}}
> \renewcommand{\labelenumiii}{http://www.cnn.com/\theenumii. 
> \theenumiii.}
> %\renewcommand{\p at enumiii}{\theenumii}
>
> %%%%%%%%%%%%%%%%%%%%    Page layout   %%%%%%%%%%%%%%%%%%%%
>
> %\markright{First Draft}
> %\pagestyle{myheadings}
>
> \hfuzz1.5pc % Don't bother to report overfull boxes if overage is <  
> 1pc
> %\vfuzz3pc % only for draftheadstyle
>
> %\show \serieslogo@
> %\show \makeatletter
>
> %\makeatletter
> %\renewcommand{\serieslogo@}{\begin{minipage}{8cm}
> %To appear in \\ {\sc Journal of Algebraic Geometry}
> %\end{minipage}}
> %\renewcommand{\@setcopyright}{}
> %\makeatother
>
>
> %\setlength{\headsep}{0pt}
> %\setlength{\headheight}{0pt}
> %\setlength{\topmargin}{0pt}
> %\setlength{\footskip}{50pt}
> \setlength{\oddsidemargin}{0in}
> \setlength{\evensidemargin}{0in}
> \setlength{\textwidth}{6.5in}
> \setlength{\textheight}{8.5in}
> \setlength{\parskip}{1mm}
> \renewcommand{\baselinestretch}{1.25}
>
> %%%%%%%%%%%%%%%%%%%%    Top Matter (amsart style)  %%%%%%%%%%%%%%%%%% 
> %%%
>
> %\date{ }
> %\title[Chow varietihttp://www.rae.es/es and Euler-Chow series]{Some  
> remarks on Chow
> %varieties and Euler-Chow series}
> %\author{E. Javier Elizondo}
> %\address{Instituto de Matem\'aticas, UNAM, Mexico}
> %\thanks{The first author was supported in part by grants UNAM-DGAPA
> %IN119298 and CONACYT 27969E}
> %\email{javier at math.unam.mx}
>
> %\author{V. Srinivas}
> %\address{School of Mathematics, Tata Institute of Fundamental  
> Research, Homi Bhabha
> %Road, Mumbai-400005, India}
> %\thanks{ Srinvias, here you have to write if you like to thanks}
> %\email{srinivas at math.tifr.res.in}
>
>
>
> \begin{document}
> %\maketitle
>
> \begin{flushright}
> Name:\underline{\hspace{7cm} }\\
> UIN:\underline{\hspace{7cm} }
> \end{flushright}%\vspace{1.5cm}
> \begin{flushleft}
> MATH-172-501
> \end{flushleft}
> \begin{center}{\Large {\bf Answers to Second Midterm}}\end{center}
> \begin{center}{\large Javier Elizondo}\end{center}\vspace{.3cm}
>
> \begin{enumerate}
> \item[I.] Find the integral\ $$ \int \sin^{2}x \, \cos^{2}x\, \, dx$$
> % Prob. 8.2 - 8
> \\{\bf  Sol.} $\sin^2 x \cos^2 x = \left( \sin x \cos x\right) ^2 =
> \left(\frac{1}{2} \sin (2x)\right)^2 =
> \frac{1}{4} \sin^2 (2x) = \frac{1}{8} \left( 1-\cos (4x)\right) $ Now
> the integral becomes $\int \frac{1}{8} \left( 1-\cos (4x)\right) \,  
> dx$ which
> is very easy to compute.
>
> \item[II.] Find the integral\ $$\int \frac{dx}{x\sqrt{x^2 + 3}}.$$
> %8.3 #15
> \\ {\bf Sol.} $x= \sqrt{3}\tan \theta$, where
> $\frac{-\pi}{2}<\theta<\frac{\pi}{2}$, and $dx = \sqrt{3}\sec^2 \theta
> \,d\theta.$ We also now that\newline  $\sqrt{3\tan^2 + 3} =
> \sqrt{3}\sqrt{\sec^2 x} = \sqrt{3} \sec x.$ Therefore the integral
> becomes\newline  $ \frac{1}{\sqrt{3}}\int \frac{\sec\theta \,
>  d\theta}{\tan\theta} =\frac{1}{\sqrt{3}}\int \csc\theta \, d\theta.$
> We use the formula written in the exam, and with the appropriate right
> rectangle we return to the variable $x$.
>
> \item[III.] Find \ $$\int \frac{x^2}{(x-3)(x+2)^2}\, \, dx$$
> %prob. 8.4-30
> \\ {\bf Sol.}
> $
> \frac{x^2}{(x-3)(x+2)2} = \frac{A}{x-3} +
> \frac{B}{x+2}+\frac{C}{(x+2)^2}
> \Longrightarrow x^2 = A(x+2)^2 +B(x-3)(x+2) + C(x-3)$. If $x=3$ we get
> $A=9/25$, if $x= -2$ we get $C=-4/5$. If we compare the coefficient of
> $x^2$ in the right hand side and left hand side polynomials of the
> equality we see that $1= A+B \Rightarrow B=16/25$. Then the integral  
> is
> equal to \newline
> $\frac{9}{25} \ln|x-3| + \frac{16}{25} \ln|x+2| + \frac{4}{5(x+2)} +
> C$.
>
> \item[IV.] Compute the improper integral $$\int_0^{\infty} xe^{-x}\,  
> dx$$
> %prob. 8.9-20
> \\ {\bf Sol.} Using parts with $du =e^{-x} dx$ and $v = x$ we obtain
> \newline $\int_0^{\infty} xe^{-x}\, dx = \lim_{t\rightarrow
>  \infty}\left( -xe^{-x} - e^{-x}\right)_0^t =  \lim_{t\rightarrow
>  \infty}\left(1-(t+1)e^{-t}\right) =1
> -\lim_{t\rightarrow\infty}\frac{t+1}{e^t}$ by L'Hôpital this last
> limit is equal to $1-\lim_{t\rightarrow\infty}\frac{1}{e^t} = 1-0=1.$
> Therefore the integral is convergent and is equal to $1$.
>
>
> \item[V.] A tank contains 100 L of pure water. Brine that contains
>  $0.1$ kg of salt per liter enters the tank at a rate of 10
>  L/min. The solution is kept thoroughly mixed and drains from the tank
>  at the same rate. How much salt is in the tank after t minutes?
> %9-Review-32
> \\ {\bf Sol.} The initial condition is $y(0)=0$ where as usual $y(t)$
> is the amount of salt at time $t$. Now,  $\frac{dy}{dt} =
> \text{rate in - rate out} =\left( 0.1 \, \times \, 10\right)  -
>  \left(\frac{y}{100}\, \times\, 10\right)  = 1 -
>  \frac{y}{10} =
>  \frac{10-y}{10} \Rightarrow\newline
>  \int\frac{dy}{10-y}=\int\frac{1}{10}dt \Rightarrow -\ln|10-y| =
>  \frac{1}{10}t +C \Rightarrow 10 - y = Ae^{-t/10}.$ The
>  initial condition implies $A=10$, therefore $y = 10\left( 1-e^{-t/ 
> 10}\right)$.
>
> \item[VI.] Solve the initial-value problem
> $$
> x^2 \frac{dy}{dx} + 2xy = \cos x, \,\,\,\, y(\pi) = 0
> $$
> %9.2-19
> \\ {\bf Sol.} $y^{\prime}=\frac{2}{x}y=\frac{\cos x}{x^2}$, and
> $I(x)=e^{\int (2/x) dx}= x^2. $ Multiplying the differential equation
> by $I(x)$ we obtain $x^2y^{\prime} + 2xy=\cos x \Rightarrow
> (x^2y)^{\prime} = \cos x \Rightarrow y = \frac{1}{x^2}\left(\int cos x
>  dx + C\right) = \frac{1}{x^2}\left(\sin x + C\right)
> \Longrightarrow  y = \frac{ \sin x}{x^2}$ where the last
> equality follows from the fact that
> the initial condition implies that $C = 0$.
> \end{enumerate}
>
> \end{document}
>
>
>
>
>
>
>       
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=================================
Adam M. Goldstein PhD MSLIS
Assistant Professor of Philosophy
Iona College
--
email 1	a.m.goldstein at mac.com
email 2	agoldstein at iona.edu
web	http://www.iona.edu/faculty/agoldstein/
tel	(914) 637-2717
post	Iona College
	Department of Philosophy
	715 North Avenue
	New Rochelle, NY 10801